X^2-275x+10350=0

Solution for X^2-275x+10350=0 equation:

X^2-275X+10350=0

a = 1; b = -275; c = +10350;
Δ = b2-4ac
Δ = -2752-4·1·10350
Δ = 34225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34225}=185$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-275)-185}{2*1}=\frac{90}{2}
=45
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-275)+185}{2*1}=\frac{460}{2}
=230
$